Then

$$\begin{aligned} \dot{\mathfrak{x}}(t) &= A\_{\mathfrak{G}} \mathfrak{x}(t) + B\_{\mathfrak{G}} \mathfrak{u}(t) \\ \mathfrak{y} &= \mathbf{C}\_{\mathfrak{G}} \mathfrak{x}(t) \end{aligned}$$
