**2.3 Selection of bearing**

In order to select a most suitable ball bearing, first, the basic dynamic load was calculated. It was multiplied by the service factor to get the basic dynamic load capacity. After finding the basic dynamic load capacity, the selection of bearing was made from the catalog of a manufacturer (**Figure 7**).

*2.3.1 Striebeck formula for the strength of a single ball in compression*

$$\mathbf{F\_e = Kd^2} \tag{9}$$

K = 7200. d = diameter of ball. Fe = 7200 � <sup>7</sup><sup>2</sup> . Fe = 352,800 N/mm<sup>2</sup> .

*2.3.2 The maximum load per ball*

$$\mathbf{F\_c = \frac{4.37}{n} \times C} \tag{10}$$

*α* ¼ nominal angle of contact*:* D ¼ diameter of outer race*:*

*DOI: http://dx.doi.org/10.5772/intechopen.92879*

material of one of the rings or any of the rolling elements.

P = weight of pulley + weight of shaft. P = total load (.400 + .800) = 1.2 kg. Life of bearing = 1800 million revolution.

Ln <sup>¼</sup> Cd P 

The life of an individual ball bearing may be defined as the number of revolutions which the bearing runs before the first evidence of fatigue develops in the

*Design and Development of Manufacturing System Design for Producing Metallic Foam*

The rating life of a group of apparently identical ball bearing as the number of revolutions that 90% of a group of bearings will complete or exceed before the first

<sup>¼</sup> <sup>14</sup>*:*<sup>8</sup>

The pulley was used to transmit power from one shaft to another by means of a

<sup>2</sup> <sup>¼</sup> <sup>12</sup>*:*<sup>3</sup> (13)

*2.3.4 Life of bearing in revolutions*

evidence of fatigue develops:

*2.3.5 Bearing number*

*2.3.6 Bearing socket*

flat belt, V-belt or rope.

**Figure 8.** *Bearing socket.*

**95**

Bore diameter = 20 mm. Outer race diameter = 47 mm.

Bearing of basic design no. = 04.

**2.4 Design of driver and driven pulleys**

Basic capacity of dynamic load = 1000 kg.

The outer diameter of the bearing race is 47 mm. The diameter of the socket bore is 47 mm (**Figure 8**).

ISI no. = 20BC02.

$$\mathbf{C} = \frac{\mathbf{F}\_c \times \mathbf{n}}{4.37} = \frac{\mathbf{K} \mathbf{n} \mathbf{d}^2}{4.37} \tag{11}$$

n = no. of balls.

C = capacity of the bearing.

$$C = \frac{7200 \times 8 \times .007^2}{4.37}.$$

$$\text{C} = 6.45 \text{ kg}.$$

$$\text{F}\_c = \frac{4.37}{8} \times 6.45$$

$$\text{Torque} = \frac{9550 \times \text{H.P}}{\text{N}} = \frac{9550 \times .75}{1380}.$$

T = 5.19 N m. where HP in kW, N in rpm.

### *2.3.3 Basic dynamic load of bearing*

$$\mathbf{C\_d = F\_c \times (n \cos \alpha)^{o.\mathcal{T}} Z^{2\circ} \mathbf{D}^{1.8}} \tag{12}$$
 
$$= \mathbf{3.46} \times (\mathbf{8 \cos 15})^{0.\mathcal{T}} \times \mathbf{47}^{1.8}.$$

Cd ¼ 14807*:*3 N*:* Cd ¼ 14*:*8 kN*:*

*Design and Development of Manufacturing System Design for Producing Metallic Foam DOI: http://dx.doi.org/10.5772/intechopen.92879*

*α* ¼ nominal angle of contact*:* D ¼ diameter of outer race*:*
