**3.6 Robust Bayesian estimation for scale parameter for Weibull distribution**

From Eq. (37) and by using the squared loss function, we get a Bayes estimator for the scale parameter as follows [12]:

$$\mathbf{E}\left(\boldsymbol{\theta}/\mathbf{n}^{\mathrm{m}},\mathbf{y}^{\mathrm{m}}\right) = \hat{\boldsymbol{\theta}}\_{\mathrm{Rob}}$$

$$\hat{\boldsymbol{\theta}}\_{\mathrm{Rob}} = \mathbf{y}^{\mathrm{m}}\tag{38}$$
